Optimal. Leaf size=210 \[ \frac{16 e^3 x^{11} \left (8 e (10 a e+b d)+3 c d^2\right )}{3465 d^6 \left (d+e x^2\right )^{11/2}}+\frac{8 e^2 x^9 \left (8 e (10 a e+b d)+3 c d^2\right )}{315 d^5 \left (d+e x^2\right )^{11/2}}+\frac{2 e x^7 \left (8 e (10 a e+b d)+3 c d^2\right )}{35 d^4 \left (d+e x^2\right )^{11/2}}+\frac{x^5 \left (8 e (10 a e+b d)+3 c d^2\right )}{15 d^3 \left (d+e x^2\right )^{11/2}}+\frac{x^3 (10 a e+b d)}{3 d^2 \left (d+e x^2\right )^{11/2}}+\frac{a x}{d \left (d+e x^2\right )^{11/2}} \]
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Rubi [A] time = 0.221537, antiderivative size = 210, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.208, Rules used = {1155, 1803, 12, 271, 264} \[ \frac{16 e^3 x^{11} \left (8 e (10 a e+b d)+3 c d^2\right )}{3465 d^6 \left (d+e x^2\right )^{11/2}}+\frac{8 e^2 x^9 \left (8 e (10 a e+b d)+3 c d^2\right )}{315 d^5 \left (d+e x^2\right )^{11/2}}+\frac{2 e x^7 \left (8 e (10 a e+b d)+3 c d^2\right )}{35 d^4 \left (d+e x^2\right )^{11/2}}+\frac{x^5 \left (8 e (10 a e+b d)+3 c d^2\right )}{15 d^3 \left (d+e x^2\right )^{11/2}}+\frac{x^3 (10 a e+b d)}{3 d^2 \left (d+e x^2\right )^{11/2}}+\frac{a x}{d \left (d+e x^2\right )^{11/2}} \]
Antiderivative was successfully verified.
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Rule 1155
Rule 1803
Rule 12
Rule 271
Rule 264
Rubi steps
\begin{align*} \int \frac{a+b x^2+c x^4}{\left (d+e x^2\right )^{13/2}} \, dx &=\frac{a x}{d \left (d+e x^2\right )^{11/2}}+\frac{\int \frac{x^2 \left (10 a e+d \left (b+c x^2\right )\right )}{\left (d+e x^2\right )^{13/2}} \, dx}{d}\\ &=\frac{a x}{d \left (d+e x^2\right )^{11/2}}+\frac{(b d+10 a e) x^3}{3 d^2 \left (d+e x^2\right )^{11/2}}+\frac{\int \frac{\left (3 c d^2+8 e (b d+10 a e)\right ) x^4}{\left (d+e x^2\right )^{13/2}} \, dx}{3 d^2}\\ &=\frac{a x}{d \left (d+e x^2\right )^{11/2}}+\frac{(b d+10 a e) x^3}{3 d^2 \left (d+e x^2\right )^{11/2}}+\frac{1}{3} \left (3 c+\frac{8 e (b d+10 a e)}{d^2}\right ) \int \frac{x^4}{\left (d+e x^2\right )^{13/2}} \, dx\\ &=\frac{a x}{d \left (d+e x^2\right )^{11/2}}+\frac{(b d+10 a e) x^3}{3 d^2 \left (d+e x^2\right )^{11/2}}+\frac{\left (3 c d^2+8 e (b d+10 a e)\right ) x^5}{15 d^3 \left (d+e x^2\right )^{11/2}}+\frac{\left (2 e \left (3 c d^2+8 e (b d+10 a e)\right )\right ) \int \frac{x^6}{\left (d+e x^2\right )^{13/2}} \, dx}{5 d^3}\\ &=\frac{a x}{d \left (d+e x^2\right )^{11/2}}+\frac{(b d+10 a e) x^3}{3 d^2 \left (d+e x^2\right )^{11/2}}+\frac{\left (3 c d^2+8 e (b d+10 a e)\right ) x^5}{15 d^3 \left (d+e x^2\right )^{11/2}}+\frac{2 e \left (3 c d^2+8 e (b d+10 a e)\right ) x^7}{35 d^4 \left (d+e x^2\right )^{11/2}}+\frac{\left (8 e^2 \left (3 c d^2+8 e (b d+10 a e)\right )\right ) \int \frac{x^8}{\left (d+e x^2\right )^{13/2}} \, dx}{35 d^4}\\ &=\frac{a x}{d \left (d+e x^2\right )^{11/2}}+\frac{(b d+10 a e) x^3}{3 d^2 \left (d+e x^2\right )^{11/2}}+\frac{\left (3 c d^2+8 e (b d+10 a e)\right ) x^5}{15 d^3 \left (d+e x^2\right )^{11/2}}+\frac{2 e \left (3 c d^2+8 e (b d+10 a e)\right ) x^7}{35 d^4 \left (d+e x^2\right )^{11/2}}+\frac{8 e^2 \left (3 c d^2+8 e (b d+10 a e)\right ) x^9}{315 d^5 \left (d+e x^2\right )^{11/2}}+\frac{\left (16 e^3 \left (3 c d^2+8 e (b d+10 a e)\right )\right ) \int \frac{x^{10}}{\left (d+e x^2\right )^{13/2}} \, dx}{315 d^5}\\ &=\frac{a x}{d \left (d+e x^2\right )^{11/2}}+\frac{(b d+10 a e) x^3}{3 d^2 \left (d+e x^2\right )^{11/2}}+\frac{\left (3 c d^2+8 e (b d+10 a e)\right ) x^5}{15 d^3 \left (d+e x^2\right )^{11/2}}+\frac{2 e \left (3 c d^2+8 e (b d+10 a e)\right ) x^7}{35 d^4 \left (d+e x^2\right )^{11/2}}+\frac{8 e^2 \left (3 c d^2+8 e (b d+10 a e)\right ) x^9}{315 d^5 \left (d+e x^2\right )^{11/2}}+\frac{16 e^3 \left (3 c d^2+8 e (b d+10 a e)\right ) x^{11}}{3465 d^6 \left (d+e x^2\right )^{11/2}}\\ \end{align*}
Mathematica [A] time = 0.145272, size = 167, normalized size = 0.8 \[ \frac{5 a \left (3168 d^2 e^3 x^7+3696 d^3 e^2 x^5+2310 d^4 e x^3+693 d^5 x+1408 d e^4 x^9+256 e^5 x^{11}\right )+d x^3 \left (b \left (1584 d^2 e^2 x^4+1848 d^3 e x^2+1155 d^4+704 d e^3 x^6+128 e^4 x^8\right )+3 c d x^2 \left (198 d^2 e x^2+231 d^3+88 d e^2 x^4+16 e^3 x^6\right )\right )}{3465 d^6 \left (d+e x^2\right )^{11/2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.006, size = 172, normalized size = 0.8 \begin{align*}{\frac{x \left ( 1280\,a{e}^{5}{x}^{10}+128\,bd{e}^{4}{x}^{10}+48\,c{d}^{2}{e}^{3}{x}^{10}+7040\,ad{e}^{4}{x}^{8}+704\,b{d}^{2}{e}^{3}{x}^{8}+264\,c{d}^{3}{e}^{2}{x}^{8}+15840\,a{d}^{2}{e}^{3}{x}^{6}+1584\,b{d}^{3}{e}^{2}{x}^{6}+594\,c{d}^{4}e{x}^{6}+18480\,a{d}^{3}{e}^{2}{x}^{4}+1848\,b{d}^{4}e{x}^{4}+693\,c{d}^{5}{x}^{4}+11550\,a{d}^{4}e{x}^{2}+1155\,b{d}^{5}{x}^{2}+3465\,a{d}^{5} \right ) }{3465\,{d}^{6}} \left ( e{x}^{2}+d \right ) ^{-{\frac{11}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.989096, size = 452, normalized size = 2.15 \begin{align*} -\frac{c x^{3}}{8 \,{\left (e x^{2} + d\right )}^{\frac{11}{2}} e} + \frac{256 \, a x}{693 \, \sqrt{e x^{2} + d} d^{6}} + \frac{128 \, a x}{693 \,{\left (e x^{2} + d\right )}^{\frac{3}{2}} d^{5}} + \frac{32 \, a x}{231 \,{\left (e x^{2} + d\right )}^{\frac{5}{2}} d^{4}} + \frac{80 \, a x}{693 \,{\left (e x^{2} + d\right )}^{\frac{7}{2}} d^{3}} + \frac{10 \, a x}{99 \,{\left (e x^{2} + d\right )}^{\frac{9}{2}} d^{2}} + \frac{a x}{11 \,{\left (e x^{2} + d\right )}^{\frac{11}{2}} d} + \frac{c x}{264 \,{\left (e x^{2} + d\right )}^{\frac{9}{2}} e^{2}} + \frac{16 \, c x}{1155 \, \sqrt{e x^{2} + d} d^{4} e^{2}} + \frac{8 \, c x}{1155 \,{\left (e x^{2} + d\right )}^{\frac{3}{2}} d^{3} e^{2}} + \frac{2 \, c x}{385 \,{\left (e x^{2} + d\right )}^{\frac{5}{2}} d^{2} e^{2}} + \frac{c x}{231 \,{\left (e x^{2} + d\right )}^{\frac{7}{2}} d e^{2}} - \frac{3 \, c d x}{88 \,{\left (e x^{2} + d\right )}^{\frac{11}{2}} e^{2}} - \frac{b x}{11 \,{\left (e x^{2} + d\right )}^{\frac{11}{2}} e} + \frac{128 \, b x}{3465 \, \sqrt{e x^{2} + d} d^{5} e} + \frac{64 \, b x}{3465 \,{\left (e x^{2} + d\right )}^{\frac{3}{2}} d^{4} e} + \frac{16 \, b x}{1155 \,{\left (e x^{2} + d\right )}^{\frac{5}{2}} d^{3} e} + \frac{8 \, b x}{693 \,{\left (e x^{2} + d\right )}^{\frac{7}{2}} d^{2} e} + \frac{b x}{99 \,{\left (e x^{2} + d\right )}^{\frac{9}{2}} d e} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 7.45462, size = 502, normalized size = 2.39 \begin{align*} \frac{{\left (16 \,{\left (3 \, c d^{2} e^{3} + 8 \, b d e^{4} + 80 \, a e^{5}\right )} x^{11} + 88 \,{\left (3 \, c d^{3} e^{2} + 8 \, b d^{2} e^{3} + 80 \, a d e^{4}\right )} x^{9} + 198 \,{\left (3 \, c d^{4} e + 8 \, b d^{3} e^{2} + 80 \, a d^{2} e^{3}\right )} x^{7} + 3465 \, a d^{5} x + 231 \,{\left (3 \, c d^{5} + 8 \, b d^{4} e + 80 \, a d^{3} e^{2}\right )} x^{5} + 1155 \,{\left (b d^{5} + 10 \, a d^{4} e\right )} x^{3}\right )} \sqrt{e x^{2} + d}}{3465 \,{\left (d^{6} e^{6} x^{12} + 6 \, d^{7} e^{5} x^{10} + 15 \, d^{8} e^{4} x^{8} + 20 \, d^{9} e^{3} x^{6} + 15 \, d^{10} e^{2} x^{4} + 6 \, d^{11} e x^{2} + d^{12}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.19784, size = 255, normalized size = 1.21 \begin{align*} \frac{{\left ({\left ({\left (2 \,{\left (4 \, x^{2}{\left (\frac{2 \,{\left (3 \, c d^{2} e^{8} + 8 \, b d e^{9} + 80 \, a e^{10}\right )} x^{2} e^{\left (-5\right )}}{d^{6}} + \frac{11 \,{\left (3 \, c d^{3} e^{7} + 8 \, b d^{2} e^{8} + 80 \, a d e^{9}\right )} e^{\left (-5\right )}}{d^{6}}\right )} + \frac{99 \,{\left (3 \, c d^{4} e^{6} + 8 \, b d^{3} e^{7} + 80 \, a d^{2} e^{8}\right )} e^{\left (-5\right )}}{d^{6}}\right )} x^{2} + \frac{231 \,{\left (3 \, c d^{5} e^{5} + 8 \, b d^{4} e^{6} + 80 \, a d^{3} e^{7}\right )} e^{\left (-5\right )}}{d^{6}}\right )} x^{2} + \frac{1155 \,{\left (b d^{5} e^{5} + 10 \, a d^{4} e^{6}\right )} e^{\left (-5\right )}}{d^{6}}\right )} x^{2} + \frac{3465 \, a}{d}\right )} x}{3465 \,{\left (x^{2} e + d\right )}^{\frac{11}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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